Here I write a mixed code (additional & subtraction) both. Where I use 4 variable that is for integer number. If anyone wants to use floating point number or double number. Then just write float a,b,c,d,sum. then write your code and use %f  for taking your floating or double number. You can also use more variable that you want. If you have to need more variable then you have to use array[ ]. That is different.


#include<stdio.h>
int main()

{
    int a,b,c,d,mix;

    printf("Please enter your 1st value: ");
    scanf("%d",&a);
    printf("Please enter your 2nd value: ");
    scanf("%d",&b);
    printf("Please enter your 3rd value: ");
    scanf("%d",&c);
    printf("Please enter your 4th value: ");
    scanf("%d",&d);

    mix=a+b-c+d;
    printf("\nYour total number is: %d\n",mix);


    return 0;


}

[N.T: Please notice that I just change the sign of (+) or (-) and same code as addition and subtraction . ]

Output of above code.

Here I write a code for subtraction. Where I use 4 variable that is for integer number. If anyone wants to use floating point number or double number. Then just write float a,b,c,d,sum. then write your code and use %f  for taking your floating or double number. You can also use more variable that you want. If you have to need more variable then you have to use array[ ]. That is different.


#include<stdio.h>
int main()

{
    int a,b,c,d,sub;

    printf("Please enter your 1st value: ");
    scanf("%d",&a);
    printf("Please enter your 2nd value: ");
    scanf("%d",&b);
    printf("Please enter your 3rd value: ");
    scanf("%d",&c);
    printf("Please enter your 4th value: ");
    scanf("%d",&d);

    sub=a-b-c-d;
    printf("\nYour total number is: %d\n",sub);


    return 0;


}


[N.T: Please notice that I just change the sign of (+) to (-) and same code as addition. ]

Output of above code.

Here I write a code for addition. Where I use 4 variable that is for integer number. If anyone wants to use floating point number or double number. Then just write float a,b,c,d,sum. then write your code and use %f  for taking your floating or double number. You can also use more variable that you want. If you have to need more variable then you have to use array[ ]. That is different.



#include<stdio.h>
int main()

{
    int a,b,c,d,sum;

    printf("Please enter your 1st value: ");
    scanf("%d",&a);
    printf("Please enter your 2nd value: ");
    scanf("%d",&b);
    printf("Please enter your 3rd value: ");
    scanf("%d",&c);
    printf("Please enter your 4th value: ");
    scanf("%d",&d);

    sum=a+b+c+d;
    printf("\nYour total number is: %d\n",sum);


    return 0;


}

Output of above code.

Design an x-y plot for the following where the values of x are from 0 to 20pi with a spacing of pi/100.

Question:

       Design an x-y plot for the following where the values of x are from 0 to 20pi with a spacing of           pi/100.

a.           y=x.sin(x)

b.          z=x.cos(x)

c.          convert the above 2D into a 3D plot using z as the third axis

To accept two numbers from the user and display Armstrong numbers between these two numbers

Question:

To accept two numbers from the user and display Armstrong numbers between these two numbers

  Answer:

a = input(' Enter your 1st number: ');

b = input('\n Enter your 2st number: ');

for i = a:b

if isprime(i)

fprintf('%d, ', i)

end

end

fprintf('\n')

Output:

                  Enter your 1st number: 1

                  Enter your 2st number: 100

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 

To accept two numbers from the user and display perfect numbers between these two numbers

Question:

To accept two numbers from the user and display perfect numbers between these two numbers

clc

num1 =input(' Enter your 1st number: ');

num2 =input('\n Enter your 2st number: ');

output = zeros(1,num2);

for i = num1:num2

if true

end

test = 1:i-1;

if (sum(test(mod(i,test) == 0)) == i)

output(i) = i;

end

end

output(output == 0) = []

Output: I just write in command window

       

                  Enter your 1st number : 1

                      Enter your 2st number : 100

       output =

                      6    28

To accept two numbers from the user, display all prime numbers between these two numbers.

Question:

To accept two numbers from the user, display all prime numbers between these two numbers.


     Answer:

    clc

    num1 =input(' Enter your 1st number: ');

    num2 =input('\n Enter your 2st number: ');

    n = num1 : num2;

    p = isprime(n);

    n(p)    %displays the prime numbers

Output: I write down in command window

               Enter your 1st number: 1

                  Enter your 2st number: 100            ;then push enter

              ans =

  Columns 1 through 19

2     3     5     7    11    13    17    19    23    29    31    37    41    43    47    53    59    61    67

Columns 20 through 25

      71    73    79    83    89    97